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QJEEM23Cha4c6: JEE Main 2023 Chemistry - Class 12 JEEM23Cha4c6 Solution: In the extraction process of copper, the product obtained after …

In the extraction process of copper, the product obtained after carrying out the reactions

(i) 2Cu2 S+3O2→2Cu2O+2SO22 \mathrm{Cu}_{2} \mathrm{~S}+3 \mathrm{O}_{2} \rightarrow 2 \mathrm{Cu}_{2} \mathrm{O}+2 \mathrm{SO}_{2}

(ii) 2Cu2O+Cu2 S→6Cu+SO22 \mathrm{Cu}_{2} \mathrm{O}+\mathrm{Cu}_{2} \mathrm{~S} \rightarrow 6 \mathrm{Cu}+\mathrm{SO}_{2} is called

Multiple Choice Options

  • A Copper matte
  • B Blister copper
  • C Reduced copper
  • D Copper scrap

Step-by-Step Verified Solution

The sequence of reactions stated here is part of the copper extraction process, specifically the smelting and conversion stages. Initially, copper sulfide (Cu 2_2 S) reacts with oxygen (O 2_2 ) to form copper(I) oxide (Cu 2_2 O) and sulfur dioxide (SO 2_2 ), according to the equation :

2Cu2S+3O2→2Cu2O+2SO2.2 \mathrm{Cu}_2 \mathrm{S} + 3 \mathrm{O}_2 \rightarrow 2 \mathrm{Cu}_2 \mathrm{O} + 2 \mathrm{SO}_2.

Subsequently, the resulting copper(I) oxide then reacts with remaining copper sulfide to yield copper (Cu) and additional sulfur dioxide :

2Cu2O+Cu2S→6Cu+SO2.2 \mathrm{Cu}_2 \mathrm{O} + \mathrm{Cu}_2 \mathrm{S} \rightarrow 6 \mathrm{Cu} + \mathrm{SO}_2.

The output of this process, which contains about 98-99% copper, is known as "blister copper". This name derives from the blister-like appearance of the copper surface, which results from the release of sulfur dioxide gas during the reaction.

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