Nitrogen Detection (Lassaigne's Test)
Nitrogen in organic compounds is detected by converting it into sodium cyanide, which further reacts with iron(II) sulfate to form sodium hexacyanoferrate(II). By reacting this with iron(III) ions, Prussian blue is formed:
amp;Na+C+N→NaCNamp;6NaCN+FeSO4→Na4[Fe(CN)6]+Na2SO4amp;Na4[Fe(CN)6]+Fe3+→Fe4[Fe(CN)6]3 (Prussian blue)
Sulphur Detection
Sulphur can be detected using Sodium nitroprusside:
Na2[Fe(CN)5NO]+Na2S→Na4[Fe(CN)5NOS] [Purple]
Phosphorous Detection
Phosphorus detection involves reaction with ammonium molybdate to form a canary yellow compound:
amp;Na3PO4+3HNO3→H3PO4+3NaNO3amp;H3PO4+12(NH4)2MoO4+21HNO3→amp;(NH4)3PO4⋅12MoO3+21NH4NO3+12H2O (canary yellow)
Halogen Detection
Halogens react with silver nitrate to form specific colored precipitates:
amp;NaCl+AgNO3(aq)→AgCl+NaNO3 (White)amp;NaBr+AgNO3(aq)→AgBr+NaNO3 (Pale yellow)amp;NaI+AgNO3(aq)→AgI+NaNO3 (Yellow)
Based on the above reactions, the correct matching is:
Option A
A-III (Nitrogen), B-I (Sulphur), C-IV (Phosphorous), D-II (Halogen).