Verified Solution • 2025–26 Session moderate

QJEEM23Ch8e5b: JEE Main 2023 Chemistry - Class 11 JEEM23Ch8e5b Solution: The total number of isoelectronic species from the given set is …

The total number of isoelectronic species from the given set is ___________.

O2−,F−,Al,Mg2+,Na+,O+,Mg,Al3+,F\mathrm{O}^{2-}, \mathrm{F}^{-}, \mathrm{Al}, \mathrm{Mg}^{2+}, \mathrm{Na}^{+}, \mathrm{O}^{+}, \mathrm{Mg}, \mathrm{Al}^{3+}, \mathrm{F}

Step-by-Step Verified Solution

Isoelectronic species are atoms, ions or molecules that have the same number of electrons. To find the isoelectronic species from the given set, we need to determine the number of electrons in each species.

The electron configuration of each species is:

- O2−\mathrm{O}^{2-} : 1s2 2s2 2p61s^2\ 2s^2\ 2p^6 , 10 electrons

- F−\mathrm{F}^{-} : 1s2 2s2 2p61s^2\ 2s^2\ 2p^6 , 10 electrons

- Al\mathrm{Al} : 1s2 2s2 2p6 3s2 3p11s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^1 , 13 electrons

- Mg2+\mathrm{Mg}^{2+} : 1s2 2s2 2p61s^2\ 2s^2\ 2p^6 , 10 electrons

- Na+\mathrm{Na}^{+} : 1s2 2s2 2p61s^2\ 2s^2\ 2p^6 , 10 electrons

- O+\mathrm{O}^{+} : 1s2 2s2 2p31s^2\ 2s^2\ 2p^3 , 7 electrons

- Mg\mathrm{Mg} : 1s2 2s2 2p6 3s21s^2\ 2s^2\ 2p^6\ 3s^2 , 12 electrons

- Al3+\mathrm{Al}^{3+} : 1s2 2s2 2p61s^2\ 2s^2\ 2p^6 , 10 electrons

- F\mathrm{F} : 1s2 2s2 2p51s^2\ 2s^2\ 2p^5 , 9 electrons

Related Learning Resources & Exam Preparation