QJEEM23Ch8ca1: JEE Main 2023 Chemistry - Class 11 JEEM23Ch8ca1 Solution: Given below are two statements: Statement-I : Methane and steam …
Given below are two statements:
Statement-I : Methane and steam passed over a heated
Statement-II : Sodium nitrite reacts with
In the light of the above statements, choose the most appropriate answer from the options given below :
Multiple Choice Options
- A Statement I is correct but Statement II is incorrect
- B Both the statements I and II are incorrect
- C Both the statements I and II are correct
- D Statement I is incorrect but Statement II is correct
Step-by-Step Verified Solution
Let's consider each statement:
Statement-I : Methane (CH₄) and steam (H₂O) can indeed react in the presence of a heated nickel catalyst to produce carbon monoxide (CO) and hydrogen gas (H₂). This is known as the steam reforming or steam methane reforming reaction and is industrially significant for hydrogen production. Hence, Statement-I is correct.
Statement-II : Sodium nitrite (NaNO₂) reacts with ammonium chloride (NH₄Cl) to produce nitrogen gas (N₂), water (H₂O), and sodium chloride (NaCl). This is a standard reaction that is often used in inorganic chemistry to produce nitrogen gas. Hence, Statement-II is also correct.
Therefore, the correct answer is Option C: Both the statements I and II are correct.