QJEEM23Ch8141: JEE Main 2023 Chemistry - Class 12 JEEM23Ch8141 Solution: The total change in the oxidation state of manganese involved…

The reaction of $\mathrm{KMnO}_4$ and potassium iodide ( $\mathrm{KI}$ ) in acidic medium can be represented as follows:

$\mathrm{MnO_4^-} + \mathrm{I^-} + \mathrm{H^+} \rightarrow \mathrm{Mn^{2+}} + \mathrm{I_2} + \mathrm{H_2O}$

In this reaction, $\mathrm{KMnO}_4$ acts as an oxidizing agent, while $\mathrm{KI}$ acts as a reducing agent. The oxidation state of manganese changes from +7 in $\mathrm{KMnO_4}$ to +2 in $\mathrm{Mn^{2+}}$ , which is a reduction of 5 units.

Therefore, the total change in the oxidation state of manganese involved in the reaction is $\boxed{5}$ .