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QJEEM23Ch7f8f: JEE Main 2023 Chemistry - Class 11 JEEM23Ch7f8f Solution: At , the solubility of silver chloride in water is . The value…

At 298 K298 \mathrm{~K} , the solubility of silver chloride in water is 1.434×10−3 g L−11.434 \times 10^{-3} \mathrm{~g} \mathrm{~L}^{-1} . The value of −log⁡Ksp-\log \mathrm{K}_{\mathrm{sp}} for silver chloride is _________.

(Given mass of Ag\mathrm{Ag} is 107.9 g mol−1107.9 \mathrm{~g} \mathrm{~mol}^{-1} and mass of Cl\mathrm{Cl} is 35.5 g mol−135.5 \mathrm{~g} \mathrm{~mol}^{-1} )

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JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Ionic Equilibrium Question 31 English Explanation

amp;Ksp=(Ag+)(Cl−)=S×S=S2amp; S=Kspamp;S=1.434×10−3143.4=10−5amp; Ksp=S2=10−10amp;⇒−log⁡(Ksp)=−log⁡(10−10)=10\begin{aligned}& \mathrm{K}_{\mathrm{sp}}=\left(\mathrm{Ag}^{+}\right)\left(\mathrm{Cl}^{-}\right)=\mathrm{S} \times \mathrm{S}=\mathrm{S}^2 \\\\& \mathrm{~S}=\sqrt{\mathrm{K}_{\mathrm{sp}}} \\\\& \mathrm{S}=\frac{1.434 \times 10^{-3}}{143.4}=10^{-5} \\\\& \mathrm{~K}_{\mathrm{sp}}=\mathrm{S}^2=10^{-10} \\\\& \Rightarrow-\log \left(\mathrm{K}_{\mathrm{sp}}\right)=-\log \left(10^{-10}\right)=10\end{aligned}

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