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QJEEM23Ch6bd1: JEE Main 2023 Chemistry - Class 11 JEEM23Ch6bd1 Solution: The energy of one mole of photons of radiation of frequency 2 × …

The energy of one mole of photons of radiation of frequency 2×1012 Hz in J mol−1 is ___________. (Nearest integer)

[Given : h=6.626×10−34 Js

NA=6.022×1023 mol−1]

Step-by-Step Verified Solution

E=nhv

=(6.022×1023)(6.626×10−34)×(2×1012)

=798.03 J

≈ 798 J

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