QJEEM23Ch6ac6: JEE Main 2023 Chemistry - Class 11 JEEM23Ch6ac6 Solution: A solution is prepared by adding of " " to 1 mole of water.…

First, we need to calculate the mass of 1 mole of water (H₂O). The molecular weight of water is 18 g/mol, so 1 mole of water weighs 18 g.

The total mass of the solution is the mass of "X" plus the mass of water, which is 2 g + 18 g = 20 g.

We can calculate the mass percent of "X" in the solution with the following formula:

$\text{Mass percent of "X"} = \left(\frac{\text{mass of "X"}}{\text{total mass of solution}}\right) \times 100\%$

Substitute the given values into the formula :

$\text{Mass percent of "X"} = \left(\frac{2 \, \text{g}}{20 \, \text{g}}\right) \times 100\% = 10\%$

Therefore, Option B, $10\%$ , is the correct answer.