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QJEEM23Ch6a80: JEE Main 2023 Chemistry - Class 11 JEEM23Ch6a80 Solution: On complete combustion, of an organic compound gave of . The %…

On complete combustion, 0.492 g0.492 \mathrm{~g} of an organic compound gave 0.792 g0.792 \mathrm{~g} of CO2\mathrm{CO}_{2} . The % of carbon in the organic compound is ___________ (Nearest integer)

Step-by-Step Verified Solution

Weight of C\mathrm{C} in 0.792gm0.792 \mathrm{gm} CO2\mathrm{CO}_2

amp;=1244×0.792=0.216amp;% of C in compound =0.2160.492×100amp;=43.90%\begin{aligned}& =\frac{12}{44} \times 0.792=0.216 \\\\& \% \text { of } C \text { in compound }=\frac{0.216}{0.492} \times 100 \\\\& =43.90 \%\end{aligned}

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