Verified Solution • 2025–26 Session moderate

QJEEM23Ch68ac: JEE Main 2023 Chemistry - Class 12 JEEM23Ch68ac Solution: A solution of when treated with gives a prussium blue…

A solution of FeCl3\mathrm{FeCl_3} when treated with K4[Fe(CN)6]\mathrm{K_4[Fe(CN)_6]} gives a prussium blue precipitate due to the formation of :

Multiple Choice Options

  • A Fe[Fe(CN)6]\mathrm{Fe[Fe(CN)_{6}]}
  • B Fe4[Fe(CN)6]3\mathrm{Fe_{4}[Fe(CN)_{6}]_{3}}
  • C Fe3[Fe(CN)6]2\mathrm{Fe_{3}[Fe(CN)_{6}]_{2}}
  • D K[Fe2(CN)6]\mathrm{K[Fe_{2}(CN)_{6}]}

Step-by-Step Verified Solution

Fe3++[Fe(CN)6]4−⟶Fe4[Fe(CN)6]3\mathrm{Fe}^{3+}+\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-} \longrightarrow \mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3} (Prussium Blue)

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