Verified Solution • 2025–26 Session
moderate
QJEEM23Ch686f: JEE Main 2023 Chemistry - Class 11 JEEM23Ch686f Solution: 25 mL of silver nitrate solution (1M) is added dropwise…
Multiple Choice Options
- A I− only
- B K+ only
- C Ag+ and I− both
- D NO3− only
Step-by-Step Verified Solution
The reaction between silver nitrate (AgNO3) and potassium iodide (KI) forms silver iodide (AgI), which is practically insoluble in water. The reaction is as follows :
AgNO3(aq) + KI(aq) → AgI(s) + KNO3(aq)
Although the reaction stoichiometry indicates that iodide ions (I-) and silver ions (Ag+) are produced, silver iodide (AgI) precipitates out of the solution due to its low solubility, and very little Ag+ and I- ions remain in the solution. Hence, their concentration in the solution will be negligible.
So, the correct answer should be :
Option C : Ag+ and I- both
AgNO3(aq) + KI(aq) → AgI(s) + KNO3(aq)
Although the reaction stoichiometry indicates that iodide ions (I-) and silver ions (Ag+) are produced, silver iodide (AgI) precipitates out of the solution due to its low solubility, and very little Ag+ and I- ions remain in the solution. Hence, their concentration in the solution will be negligible.
So, the correct answer should be :
Option C : Ag+ and I- both