Verified Solution • 2025–26 Session moderate

QJEEM23Ch67ad: JEE Main 2023 Chemistry - Class 12 JEEM23Ch67ad Solution: Which of the following expressions is correct in case of a unit …

Which of the following expressions is correct in case of a CsCl\mathrm{CsCl} unit cell (edge length 'a')?

Multiple Choice Options

  • A rCs++rCl−=32a\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{\sqrt{3}}{2} \mathrm{a}
  • B rCs++rCl−=a2\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{\mathrm{a}}{\sqrt{2}}
  • C rCs++rCl−=a\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\mathrm{a}
  • D rCs++rCl−=a2\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{\mathrm{a}}{2}

Step-by-Step Verified Solution

CsCl\mathrm{CsCl} has body centered type structure in which Cs+\mathrm{Cs}^{+} occupies at corner of a cube and Cl−\mathrm{Cl}^{-} occupies the centre of the cube.

2rCs++2rCl−=3a2 \mathrm{r}_{\mathrm{Cs}^{+}}+2 \mathrm{r}_{\mathrm{Cl}^{-}}=\sqrt{3} \mathrm{a} (where a is the edge length of the cube)

rCs++rCl−=32a

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