QJEEM23Ch67a2: JEE Main 2023 Chemistry - Class 12 JEEM23Ch67a2 Solution: Match List I with List II .tg…
Match List I with List II
| LIST I (Examples) | LIST II (Type) | ||
|---|---|---|---|
| A. | 2-chloro-1,3- butadiene | I. | Biodegradable polymer |
| B. | Nylon 2-nylon 6 | II. | Synthetic Rubber |
| C. | Polyacrylonitrile | III. | Polyester |
| D. | Dacron | IV. | Addition Polymer |
Choose the correct answer from the options given below:
Multiple Choice Options
- A A-II, B-IV, C-I, D-III
- B A-IV, B-I, C-III, D-II
- C A-II, B-I, C-IV, D-III
- D A-IV, B-III, C-I, D-II
Step-by-Step Verified Solution
Let's look at each example in List I and try to identify its type:
A. 2-chloro-1,3-butadiene: This is an example of a synthetic rubber, which is a type of polymer.
B. Nylon 2-nylon 6: This is a type of nylon polymer, which is a type of polyester.
C. Polyacrylonitrile: This is an example of a biodegradable polymer, which can be broken down by microorganisms.
D. Dacron: This is an example of an addition polymer, which is a polymer formed by the addition of monomers.
Now, let's look at the types in List II and match them with their corresponding examples:
I. Biodegradable polymer: This matches with example C, which is Polyacrylonitrile.
II. Synthetic Rubber: This matches with example A, which is 2-chloro-1,3-butadiene.
III. Polyester: This matches with example B, which is Nylon 2-nylon 6.
IV. Addition polymer: This matches with example D, which is Dacron.
Therefore, the correct matching of List I with List II is:
A - II (Synthetic rubber)
B - III (Polyester)
C - I (Biodegradable polymer)
D - IV (Addition polymer)
Hence, the correct answer is A-II, B-I, C-IV, D-III.