Verified Solution • 2025–26 Session moderate

QJEEM23Ch639b: JEE Main 2023 Chemistry - Class 11 JEEM23Ch639b Solution: The density of solution of is . Molality of the solution is…

The density of 3M3 \mathrm{M} solution of NaCl\mathrm{NaCl} is 1.0 g mL−11.0 \mathrm{~g} \mathrm{~mL}^{-1} . Molality of the solution is ____________ ×10−2 m\times 10^{-2} \mathrm{~m} . (Nearest integer).

Given: Molar mass of Na\mathrm{Na} and Cl\mathrm{Cl} is 2323 and 35.5 g mol−135.5 \mathrm{~g} \mathrm{~mol}^{-1} respectively.

Step-by-Step Verified Solution

m=1000M1000ρ−M.mw=1000×31000−3×(58.5)\mathrm{m}=\frac{1000 \mathrm{M}}{1000 \rho-\mathrm{M} . \mathrm{m_w}}=\frac{1000 \times 3}{1000-3 \times(58.5)} =3000(1000−175.5)=3.638=\frac{3000}{(1000-175.5)}=3.638

=363.8×10−2=363.8 \times 10^{-2}

Nearest integer =364=364

Related Learning Resources & Exam Preparation