QJEEM23Ch577f: JEE Main 2023 Chemistry - Class 11 JEEM23Ch577f Solution: In which of the following processes, the bond order increases…

Let's analyze each option:

Option A: $\mathrm{O}_{2} \rightarrow \mathrm{O}_{2}^{2-}$

The bond order of $\mathrm{O}_{2}$ is 2 and it is paramagnetic. When two electrons are added to form $\mathrm{O}_{2}^{2-}$ , the bond order becomes 1 (decreases) and it becomes diamagnetic. This option does not meet the required conditions.

Option B: $\mathrm{N}_{2} \rightarrow \mathrm{N}_{2}^{+}$

The bond order of $\mathrm{N}_{2}$ is 3 and it is diamagnetic. When one electron is removed to form $\mathrm{N}_{2}^{+}$ , the bond order becomes 2.5 (decreases) and it remains diamagnetic. This option does not meet the required conditions.

Option C: $\mathrm{NO} \rightarrow \mathrm{NO}^{+}$

The bond order of $\mathrm{NO}$ is 2.5 and it is paramagnetic. When one electron is removed to form $\mathrm{NO}^{+}$ , the bond order becomes 3 (increases) and it becomes diamagnetic. This option meets the required conditions.

Option D: $\mathrm{O}_{2} \rightarrow \mathrm{O}_{2}^{+}$

The bond order of $\mathrm{O}_{2}$ is 2 and it is paramagnetic. When one electron is removed to form $\mathrm{O}_{2}^{+}$ , the bond order becomes 2.5 (increases) and it remains paramagnetic. This option does not meet the required conditions.

Therefore, the correct answer is $\mathrm{NO} \rightarrow \mathrm{NO}^{+}$ .