Verified Solution • 2025–26 Session moderate

QJEEM23Ch56e3: JEE Main 2023 Chemistry - Class 11 JEEM23Ch56e3 Solution: The total pressure of a mixture of non-reacting gases and in a…

The total pressure of a mixture of non-reacting gases X(0.6 g)\mathrm{X}(0.6 \mathrm{~g}) and Y(0.45 g)\mathrm{Y}(0.45 \mathrm{~g}) in a vessel is 740 mm740 \mathrm{~mm} of Hg\mathrm{Hg} .

The partial pressure of the gas X\mathrm{X} is _______ mm\mathrm{mm} of Hg\mathrm{Hg} . (Nearest Integer)

(Given : molar mass X=20\mathrm{X}=20 and Y=45 g mol−1\mathrm{Y}=45 \mathrm{~g} \mathrm{~mol}^{-1} )

Step-by-Step Verified Solution

amp;PTotal =740 mm of Hgamp;PX=( mole fraction of X)PTotal amp;nX=0.620=0.03amp;nY=0.4545=0.01amp; Mole fraction of X=0.030.01+0.03=34amp; Partial pressure of X=34×740amp;=555 mm of Hg\begin{aligned}& P_{\text {Total }}=740 \mathrm{~mm} \text { of } \mathrm{Hg} \\\\& \mathrm{P}_{\mathrm{X}}= (\text { mole fraction of } X) \mathrm{P}_{\text {Total }} \\\\& \mathrm{n}_X=\frac{0.6}{20}=0.03 \\\\& \mathrm{n}_Y=\frac{0.45}{45}=0.01 \\\\& \text { Mole fraction of } X=\frac{0.03}{0.01+0.03}=\frac{3}{4} \\\\& \text { Partial pressure of } X=\frac{3}{4} \times 740 \\\\& =555 \mathrm{~mm} \text { of } \mathrm{Hg}\end{aligned}

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