Verified Solution • 2025–26 Session moderate

QJEEM23Ch54e8: JEE Main 2023 Chemistry - Class 12 JEEM23Ch54e8 Solution: = __________

$\mathrm{Nd^{2+}}$ = __________

Multiple Choice Options

A $\mathrm{4f^4 6s^2}$
B $\mathrm{4f^3}$
C $\mathrm{4f^4}$
D $\mathrm{4f^2 6s^2}$

Step-by-Step Verified Solution

Nd(60) = [Xe] 4f⁴ 5d⁰ 6s²

Nd²⁺ = [Xe] 4f⁴ 5d⁰ 5s⁰

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