Verified Solution • 2025–26 Session moderate

QJEEM23Ch4db8: JEE Main 2023 Chemistry - Class 11 JEEM23Ch4db8 Solution: 5 g of NaOH was dissolved in deionized water to prepare a 450…

5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0.1 M solution? _____________

Given : Molar Mass of Na, O and H is 23, 16 and 1 g mol −1^{-1} respectively

Step-by-Step Verified Solution

Molarity of solution =5(40)(1000)(450)=\frac{5}{(40)} \frac{(1000)}{(450)}

⇒M×V=500×.1\Rightarrow M \times V=500 \times .1

⇒540×1000450×V=500×0.1\Rightarrow \frac{5}{40} \times \frac{1000}{450} \times V=500 \times 0.1

V=180 mL\mathrm{V}=180 \mathrm{~mL}

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