QJEEM23Ch4ac7: JEE Main 2023 Chemistry - Class 12 JEEM23Ch4ac7 Solution: The IUPAC name of is:-
The IUPAC name of is:-
Multiple Choice Options
- A Potassium tris(oxalato)cobalt(III)
- B Potassium tris(oxalato)cobaltate(III)
- C Potassium trioxalatocobaltate(III)
- D Potassium trioxalatocobalt(III)
Step-by-Step Verified Solution
To determine the IUPAC name of the compound K₃[Co(C₂O₄)₃], let's follow the nomenclature rules for coordination compounds:
Identify the Cation and Anion: The compound consists of potassium ions (K⁺) and a complex anion [Co(C₂O₄)₃]³⁻.
Name the Cation First: The cation is named first. So, we start with "Potassium."
Determine the Ligand Name: The ligand C₂O₄²⁻ is called "oxalato."
Count the Number of Ligands: There are three oxalato ligands. Since "oxalato" does not contain any numerical prefixes (like di-, tri-), we use the prefixes "di-", "tri-", etc., for simple ligands. So, we use "trioxalato."
Name the Central Metal Atom: Since the complex ion is an anion, the metal name ends with the suffix "-ate." Therefore, "cobalt" becomes "cobaltate."
Specify the Oxidation State: The oxidation state of cobalt in this complex can be calculated:
Let the oxidation state of Co be x.
Each oxalato ligand has a charge of -2.
The overall charge of the complex ion is -3.
So, x + 3(-2) = -3 ⇒ x -6 = -3 ⇒ x = +3.
Therefore, we indicate the oxidation state as (III).
Combining all these, the IUPAC name is Potassium trioxalatocobaltate(III).
Answer: Option C
Potassium trioxalatocobaltate(III)