QJEEM23Ch4428: JEE Main 2023 Chemistry - Class 12 JEEM23Ch4428 Solution: Coagulating value of the electrolytes and for are 0.09 and…

The coagulating power of an electrolyte is inversely proportional to its coagulating value. That is,

$\text{Coagulating power} = \frac{1}{\text{Coagulating value}}$

Therefore, the coagulating power of AlCl₃ is $\frac{1}{0.09}$

and the coagulating power of NaCl is $\frac{1}{50.04}$

We are asked to find the factor by which the coagulating power of AlCl₃ is greater than the coagulating power of NaCl. This factor is given by the ratio

$x = \frac{\text{Coagulating power of AlCl₃}}{\text{Coagulating power of NaCl}} = \frac{\frac{1}{0.09}}{\frac{1}{50.04}} = \frac{50.04}{0.09}$

$x = \frac{50.04}{0.09} \approx 556.22$

So, the coagulating power of AlCl₃ is approximately 556 times the coagulating power of NaCl.

However, since the problem asks for the nearest integer, the answer would be 556.