QJEEM23Ch4379: JEE Main 2023 Chemistry - Class 12 JEEM23Ch4379 Solution: The resistivity of a solution of an electrolyte is . Its molar…

Question

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The resistivity of a

0.8 \mathrm{M}

solution of an electrolyte is

5 \times 10^{-3} \Omega~ \mathrm{cm}

.

Its molar conductivity is _________

\times 10^{4}~ \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}

. (Nearest integer)

Accepted Answer

\begin{aligned} Molar conductivity & = \frac{k \times 1000}{C} \\ = \frac{\frac{1}{5 \times 10^{- 3}} \times 1000}{0.8} \\ = \frac{10^{6}}{4} = 0.25 \times 10^{6} \\ = 25 \times 10^{4} Ω^{- 1} {cm}^{2} {mol}^{- 1} \end{aligned}

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