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QJEEM23Ch426e: JEE Main 2023 Chemistry - Class 11 JEEM23Ch426e Solution: The density of a monobasic strong acid (Molar mass 24.2 g/mol)…

The density of a monobasic strong acid (Molar mass 24.2 g/mol) is 1.21 kg/L. The volume of its solution required for the complete neutralization of 25 mL of 0.24 M NaOH is __________ ×\times 10 −2^{-2} mL (Nearest integer)

Step-by-Step Verified Solution

amp; millimole of NaOH=0.24×25amp;∴ millimole of acid =0.24×25amp;⇒ mass of acid =0.24×25×24.2mgamp; for pure acid, amp;V=wd;(d=1.21 kg/L=1.21 g/ml)amp;∴V=0.24×25×24.21.12×10−3amp;=120×10−3 mlamp;=12×10−2 ml\begin{aligned}& \text { millimole of } \mathrm{NaOH}=0.24 \times 25 \\\\& \therefore \text { millimole of acid }=0.24 \times 25 \\\\& \Rightarrow \text { mass of acid }=0.24 \times 25 \times 24.2 \mathrm{mg} \\\\& \text { for pure acid, } \\\\& \mathrm{V}=\frac{\mathrm{w}}{\mathrm{d}} ;(\mathrm{d}=1.21 \mathrm{~kg} / \mathrm{L}=1.21 \mathrm{~g} / \mathrm{ml}) \\\\& \therefore \mathrm{V}=\frac{0.24 \times 25 \times 24.2}{1.12} \times 10^{-3} \\\\& =120 \times 10^{-3} ~\mathrm{ml} \\\\& =12 \times 10^{-2} ~\mathrm{ml}\end{aligned}

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