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QJEEM23Ch3dec: JEE Main 2023 Chemistry - Class 12 JEEM23Ch3dec Solution: In the above conversion of compound to product , the sequence…

JEE Main 2023 (Online) 30th January Evening Shift Chemistry - Compounds Containing Nitrogen Question 68 English

In the above conversion of compound (X)(\mathrm{X}) to product (Y)(\mathrm{Y}) , the sequence of reagents to be used will be:

Multiple Choice Options

  • A  (i) Br2,Fe (ii) Fe,H+(iii) LiAIH4\begin{array}{lll}\text { (i) } \mathrm{Br}_2, \mathrm{Fe} & \text { (ii) } \mathrm{Fe}, \mathrm{H}^{+} & \text {(iii) } \mathrm{LiAIH}_4\end{array}
  • B  (i) Br2(aq) (ii) LiAIH4 (iii) H3O+\begin{array}{lll}\text { (i) } \mathrm{Br}_2(\mathrm{aq}) & \text { (ii) } \mathrm{LiAIH}_4 & \text { (iii) } \mathrm{H}_3 \mathrm{O}^{+}\end{array}
  • C (i) Fe,H+\mathrm{Fe}, \mathrm{H}^{+} (ii) Br2\mathrm{Br}_2 (aq) (iii) HNO2\mathrm{HNO}_2 (iv) H3PO2\mathrm{H}_3 \mathrm{PO}_2
  • D (i) Fe,H+\mathrm{Fe}, \mathrm{H}^{+} (ii) Br2(aq)\mathrm{Br}_2(\mathrm{aq}) (iii) HNO2\mathrm{HNO}_2 (iv) CuBr\mathrm{CuBr}

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JEE Main 2023 (Online) 30th January Evening Shift Chemistry - Compounds Containing Nitrogen Question 68 English Explanation

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