Verified Solution • 2025–26 Session moderate

QJEEM23Ch3739: JEE Main 2023 Chemistry - Class 12 JEEM23Ch3739 Solution: Which of the following statements are correct? (A) The M /M…

Which of the following statements are correct?

(A) The M 3+^{3+} /M 2+^{2+} reduction potential for iron is greater than manganese.

(B) The higher oxidation states of first row d-block elements get stabilized by oxide ion.

(C) Aqueous solution of Cr 2+^{2+} can liberate hydrogen from dilute acid.

(D) Magnetic moment of V 2+^{2+} is observed between 4.4 - 5.2 BM.

Choose the correct answer from the options given below :

Multiple Choice Options

  • A (B), (C) only
  • B (A), (B) only
  • C (A), (B), (D) only
  • D (C), (D) only

Step-by-Step Verified Solution

The reduction electrode potential of Mn3+/Mn2+\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+} is +1.57 V+1.57 \mathrm{~V} while that of Fe3+/Fe2+\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+} is +0.77 V+0.77 \mathrm{~V} , hence A\mathrm{A} is wrong. Higher oxidation state of smaller dd -block elements is stabilized (or say form compounds) with smaller anion oxide that can be explained by stearic reason hence BB is correct.

The oxidation electrode potential of Cr2+/Cr3+\mathrm{Cr}^{2+} / \mathrm{Cr}^{3+} is +0.41 V+0.41 \mathrm{~V} hence it can reduce H+\mathrm{H}^{+} and so liberate H2\mathrm{H}_2 . The unpaired electrons in V2+\mathrm{V}^{2+} are 3 hence the magnetic moment of V2+\mathrm{V}^{2+} will be lesser than 4.4 BM.

Hence, only BB and CC are correct.

Related Learning Resources & Exam Preparation