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QJEEM23Ch372c: JEE Main 2023 Chemistry - Class 11 JEEM23Ch372c Solution: of an organic compound with carbon will produce __________ of…

0.5 g0.5 \mathrm{~g} of an organic compound (X)(\mathrm{X}) with 60%60 \% carbon will produce __________ ×10−1 g\times 10^{-1} \mathrm{~g} of CO2\mathrm{CO}_{2} on complete combustion.

Step-by-Step Verified Solution

Mass of Carbon =12=12

Molar Mass of CO2=12+(16×2)=44\mathrm{CO}_2=12+(16 \times 2)=44

Mass of Compound =0.5 g=0.5 \mathrm{~g}

amp;% of C= Molar mass of C× Mass Of CO2 Mass Of Compound × Molar Mass Of CO2amp;60100=12×x0.5×44amp;1.1=xamp;x=11×10−1\begin{aligned}&\% \text { of } \mathrm{C} =\frac{\text { Molar mass of } \mathrm{C} \times \text { Mass Of } \mathrm{CO}_2}{\text { Mass Of Compound } \times \text { Molar Mass } \mathrm{Of} ~ \mathrm{CO}_2} \\\\&\frac{60}{100} =\frac{12 \times x}{0.5 \times 44} \\\\&1.1 =x \\\\&x =11 \times 10^{-1}\end{aligned}

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