Verified Solution • 2025–26 Session moderate

QJEEM23Ch2e5d: JEE Main 2023 Chemistry - Class 12 JEEM23Ch2e5d Solution: Match List I with List II .tg…

Match List I with List II

LIST I LIST II
A. Physisorption I. Single Layer Adsorption
B. Chemisorption II. 20−40 kJ mol−120-40 \mathrm{~kJ} \mathrm{~mol}^{-1}
C. N2( g)+3H2( g)⟶Fe(s)2NH3( g)\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Fe}(\mathrm{s})}{\longrightarrow} 2 \mathrm{NH}_{3}(\mathrm{~g}) III. Chromatography
D. Analytical Application or Adsorption IV. Heterogeneous catalysis

Choose the correct answer from the options given below:

Multiple Choice Options

  • A A - III, B - IV, C - I, D - II
  • B A - II, B - III, C - I, D - IV
  • C A - II, B - I, C - IV, D - III
  • D A - IV, B - II, C - III, D - I

Step-by-Step Verified Solution

(A) Physisorption = 20 – 40 kJ/mol and Chemisorption = 80 – 240 kJ/mol

(B) Physisorption is multi-layered and chemisorption is unimolecular layered.

(C) In heterogeneous catalysis, medium and catalyst are in different phases.

(D) Chromatography uses adsorption to purify/separate mixtures.

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