QJEEM23Ch2a24: JEE Main 2023 Chemistry - Class 12 JEEM23Ch2a24 Solution: In potassium ferrocyanide, there are ________ pairs of…

Step-by-Step Verified Solution

$\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]$


$\begin{aligned}& \mathrm{Fe}^{+2}=[\mathrm{Ar}] 3 \mathrm{~d}^6 \\\\& \mathrm{CN}^{-}=\mathrm{SFL}\end{aligned}$

$\mathrm{t}_{2 \mathrm{~g}}$ contain 6 electron so it become 3 pairs