Verified Solution • 2025–26 Session moderate

QJEEM23Ch23b3: JEE Main 2023 Chemistry - Class 11 JEEM23Ch23b3 Solution: Match List I with List II : .tg…

Match List I with List II :

List I List II
A. Slaked lime I. NaOH\mathrm{NaOH}
B. Dead burnt plaster II. Ca(OH)2\mathrm{Ca(OH)_2}
C. Caustic soda III. Na2CO3⋅10H2O\mathrm{Na_2CO_3\cdot 10H_2O}
D. Washing soda IV. CaSO4\mathrm{CaSO_4}

Choose the correct answer from the options given below :

Multiple Choice Options

  • A (A) - III, (B) - IV, (C) - II, (D) - I
  • B (A) - III, (B) - II, (C) - IV, (D) - I
  • C (A) - II, (B) - IV, (C) - I, (D) - III
  • D (A) - I, (B) - IV, (C) - II, (D) - III

Step-by-Step Verified Solution

A : Slaked lime :Ca(OH)2\quad: \mathrm{Ca}(\mathrm{OH})_{2}

B : Dead burnt plaster \quad : CaSO4\mathrm{CaSO}_{4}

C : Caustic Soda \quad : NaOH\mathrm{NaOH}

D : Washing Soda \quad : Na2CO3⋅10H2O\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}

Related Learning Resources & Exam Preparation