Verified Solution • 2025–26 Session moderate

QJEEM23Ch1711: JEE Main 2023 Chemistry - Class 11 JEEM23Ch1711 Solution: A certain quantity of real gas occupies a volume of at and when …

A certain quantity of real gas occupies a volume of 0.15 dm30.15~ \mathrm{dm}^{3} at 100 atm100 \mathrm{~atm} and 500 K500 \mathrm{~K} when its compressibility factor is 1.07 . Its volume at 300 atm and 300 K300 \mathrm{~K} (When its compressibility factor is 1.4 ) is ___________ ×10−4 dm3\times 10^{-4} ~\mathrm{dm}^{3} (Nearest integer)

Step-by-Step Verified Solution

amp;z=PVnRT;n=PVZRTamp;Z1=1.07,P1=100 atm, V1=0.15 L, T1=500 Kamp;Z2=1.4,P2=300 atm, T2=300 K, V2=?amp;P1 V1Z1RTI=P2 V2Z2RT2=namp;V2=1.41.07×.03amp;=392×10−4dm3\begin{aligned}& \mathrm{z}=\frac{\mathrm{PV}}{\mathrm{nRT}} ; \mathrm{n}=\frac{\mathrm{PV}}{\mathrm{ZRT}} \\\\& \mathrm{Z}_1=1.07, \mathrm{P}_1=100 \mathrm{~atm}, \mathrm{~V}_1=0.15 \mathrm{~L}, \mathrm{~T}_1=500 \mathrm{~K} \\\\& \mathrm{Z}_2=1.4, \mathrm{P}_2=300 \mathrm{~atm}, \mathrm{~T}_2=300 \mathrm{~K}, \mathrm{~V}_2=? \\\\& \frac{\mathrm{P}_1 \mathrm{~V}_1}{\mathrm{Z}_1 \mathrm{RT}_{\mathrm{I}}}=\frac{\mathrm{P}_2 \mathrm{~V}_2}{\mathrm{Z}_2 \mathrm{RT}_2}=\mathrm{n} \\\\& \mathrm{V}_2=\frac{1.4}{1.07} \times .03 \\\\&=392 \times 10^{-4} \mathrm{dm}^3\end{aligned}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring