Verified Solution • 2025–26 Session moderate

QJEEM23Ch0b07: JEE Main 2023 Chemistry - Class 12 JEEM23Ch0b07 Solution: Choose the correct representation of conductometric titration…

Choose the correct representation of conductometric titration of benzoic acid vs sodium hydroxide.

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/1ed89a1afa8c15d493c6baa7d8151f2819b9f703bbdeeededdfb4a97360b6a46.webp
  • B https://ik.imagekit.io/novatra/photos/4aa767b82429fa15090fc6230aab025f94175baa7c89f59c9a613ef7c1e8c766.webp
  • C https://ik.imagekit.io/novatra/photos/9bd56ff4aae91499b0468e4e2dac60c1758044cd8db9329701b8c3896d41c7d7.webp
  • D https://ik.imagekit.io/novatra/photos/5923005f0b280c470cac07c99c3192fe203baa8e60c682cf1a664a6f923c29dc.webp

Step-by-Step Verified Solution

C6H5COOH (wA) +NaOH (SB) ⟶C6H5COONa (Salt) +H2O\underset{\text { (wA) }}{\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}}+\underset{\text { (SB) }}{\mathrm{NaOH}} \longrightarrow \underset{\text { (Salt) }}{\mathrm{C}_6 \mathrm{H}_5 \mathrm{COONa}}+\mathrm{H}_2 \mathrm{O}

JEE Main 2023 (Online) 24th January Evening Shift Chemistry - Electrochemistry Question 60 English Explanation
(A) →\rightarrow (B) Free H+\mathrm{H}^{+} ions are replaced by Na⊕\mathrm{Na}^{\oplus} which decreases conductance.

(B) →\rightarrow (C) Un-dissociated benzoic acid reacts with NaOH\mathrm{NaOH} and forms salt which increases ions & conductance increases.

(C) →\rightarrow (D) After equivalence point at (3), NaOH\mathrm{NaOH} added further increases Na⊕&OH⊙\mathrm{Na}^{\oplus} \& \mathrm{OH}^{\odot} ions which further increases the conductance.

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