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QJEEM23Ch07ab: JEE Main 2023 Chemistry - Class 11 JEEM23Ch07ab Solution: One mole of an ideal monoatomic gas is subjected to changes as…

One mole of an ideal monoatomic gas is subjected to changes as shown in the graph. The magnitude of the work done (by the system or on the system) is __________ J (nearest integer)

JEE Main 2023 (Online) 24th January Evening Shift Chemistry - Thermodynamics Question 54 English

Given ; log⁡2=0.3

ln⁡10=2.3

Step-by-Step Verified Solution

1→2⇒1 \rightarrow 2 \Rightarrow Isobaric process

2→3⇒2 \rightarrow 3 \Rightarrow Isochoric process

3→1⇒3 \rightarrow 1 \Rightarrow Isothermal process

W=W1→2+W2→3+W3→1\mathrm{W}=\mathrm{W}_{1 \rightarrow 2}+\mathrm{W}_{2 \rightarrow 3}+\mathrm{W}_{3 \rightarrow 1}

=(−P(V2−V1)+0[−P1 V1ln⁡(V2 V1)])=\left(-\mathrm{P}\left(\mathrm{V}_2-\mathrm{V}_1\right)+0\left[-\mathrm{P}_1 \mathrm{~V}_1 \ln \left(\frac{\mathrm{V}_2}{\mathrm{~V}_1}\right)\right]\right)

=[−1×(40−20)+0+[−1×20ln⁡(2040)]]=\left[-1 \times(40-20)+0+\left[-1 \times 20 \ln \left(\frac{20}{40}\right)\right]\right]

=−20+20ln⁡2=-20+20 \ln 2

=−20+20×2.3×0.3=-20+20 \times 2.3 \times 0.3

=−6.2=-6.2 bar LL

∣W∣=6.2|\mathrm{W}|=6.2 bar 1=620 J1=620 \mathrm{~J}

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