Verified Solution • 2025–26 Session moderate

QJEEM23Ch0693: JEE Main 2023 Chemistry - Class 12 JEEM23Ch0693 Solution: The major product formed in the following reaction is:

The major product formed in the following reaction is:

JEE Main 2023 (Online) 8th April Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 46 English

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/3815ceaba86621615e31e726b218a36c0421b07aa602f22550cf2086d7ea1a84.webp
  • B https://ik.imagekit.io/novatra/photos/3b79a6b3fe656da3f657d2a960c137280ddaf04d1f4cc2a577f9c5e2119d7fdd.webp
  • C https://ik.imagekit.io/novatra/photos/3900037d750251866381d4319b5e3ba6a63391eb357580e3304c7f465fe8da17.webp
  • D https://ik.imagekit.io/novatra/photos/be998f88255285d5ba062934d7e34bcd4429cc9b47009e1d4ff39423d6fe51ba.webp

Step-by-Step Verified Solution

NaBH4\mathrm{NaBH}_4 (Sodium borohydride) is a weak reducing agent, it reduces aldehydes/ketones but not esters, it produces alcohols through reduction. ketones reduces to 2∘2^{\circ} alcohol.

JEE Main 2023 (Online) 8th April Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 46 English Explanation
Note: Lithium borohydride is commonly used for selective reduction of esters and lactones to the corresponding alcohol.

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring