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QJEEM23Ch00b9: JEE Main 2023 Chemistry - Class 12 JEEM23Ch00b9 Solution: The mass of NH produced when 131.8 kg of…

The mass of NH 3_3 produced when 131.8 kg of cyclohexanecarbaldehyde undergoes Tollen's test is ________ kg. (Nearest Integer)

Molar Mass of

C = 12g/mol

N = 14g/mol

O = 16g/mol

Step-by-Step Verified Solution

amp;RCHO+2[Ag(NH3)2]OH→RCOONH4+2Ag+3NH3+H2Oamp;moles =131.8×103112=1.176×103amp;1 mole of aldehyde produces 3 moles of NH3amp;1.176×103 mol aldehyde will produce amp;=3×1.176×103 moles of NH3amp;Mass of NH3 produced =3×1.176×103×17amp;=59.97×103 gamp;≈60 kg\begin{aligned}& \mathrm{RCHO}+2\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right] \mathrm{OH} \rightarrow \mathrm{RCOONH}_4+2 \mathrm{Ag} +3 \mathrm{NH}_3+\mathrm{H}_2 \mathrm{O} \\\\& \text {moles }=\frac{131.8 \times 10^3}{112}=1.176 \times 10^3 \\\\& 1 \text { mole of aldehyde produces } 3 \text { moles of } \mathrm{NH}_3 \\\\& 1.176 \times 10^3 \mathrm{~mol} \text { aldehyde will produce } \\\\& =3 \times 1.176 \times 10^3 \text { moles of } \mathrm{NH}_3 \\\\& \text {Mass of } \mathrm{NH}_3 \text { produced }=3 \times 1.176 \times 10^3 \times 17 \\\\& =59.97 \times 10^3 \mathrm{~g} \\\\& \approx 60~ \mathrm{kg}\end{aligned}

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