QJEEM23Ch0079: JEE Main 2023 Chemistry - Class 11 JEEM23Ch0079 Solution: The number of bonds in and are respectively :

Let's analyze each compound separately:

1. $\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{7}$ : This compound is also known as pyrophosphoric acid. Its structure has two phosphorus atoms (P) connected by one oxygen atom (O), forming a P-O-P bond. There are no other P-O-P bonds in its structure. Number of P-O-P bonds = 1



2. $\left(\mathrm{HPO}_{3}\right)_{3}$ : This compound is also known as cyclotriphosphoric acid. It has three phosphorus atoms and three oxygen atoms, arranged in a cyclic structure with each P atom connected to two O atoms, forming a six-membered ring. In this structure, there are three P-O-P bonds. Number of P-O-P bonds = 3



3. $\mathrm{P}_{4} \mathrm{O}_{10}$ : This compound is also known as phosphorus pentoxide. Its structure consists of four phosphorus atoms (P) and ten oxygen atoms (O) connected in a cyclic arrangement. In the structure, each phosphorus atom is connected to four oxygen atoms, with two terminal oxygen atoms and two bridging oxygen atoms. There are six P-O-P bonds in the P₄O₁₀ structure.



So, the number of P-O-P bonds in $\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{7},\left(\mathrm{HPO}_{3}\right)_{3}$ , and $\mathrm{P}_{4} \mathrm{O}_{10}$ are 1, 3, and 6, respectively.