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QJEEM22Phfea9: JEE Main 2022 Physics - Class 12 JEEM22Phfea9 Solution: Two 10 cm long, straight wires, each carrying a current of 5A…

Two 10 cm long, straight wires, each carrying a current of 5A are kept parallel to each other. If each wire experienced a force of 10 −- 5 N, then separation between the wires is ____________ cm.

Step-by-Step Verified Solution

dFdl=μ0i1i22πd{{dF} \over {dl}} = {{{\mu _0}{i_1}{i_2}} \over {2\pi d}}

So 2×10−7×5×5d=10−510×10−2{{2 \times {{10}^{ - 7}} \times 5 \times 5} \over d} = {{{{10}^{ - 5}}} \over {10 \times {{10}^{ - 2}}}}

d=2×10−7×5×510−4d = {{2 \times {{10}^{ - 7}} \times 5 \times 5} \over {{{10}^{ - 4}}}}

= 50 mm

= 5 cm

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