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QJEEM22Phfcbe: JEE Main 2022 Physics - Class 12 JEEM22Phfcbe Solution: A proton, a neutron, an electron and an α particle have same…

A proton, a neutron, an electron and an α particle have same energy. If λp, λn, λe and λa are the de Broglie's wavelengths of proton, neutron, electron and α particle respectively, then choose the correct relation from the following :

Multiple Choice Options

  • A λp = λn > λe > λa
  • B λa < λn < λp < λe
  • C λe < λp = λn > λa
  • D λe = λp = λn = λa

Step-by-Step Verified Solution

λ=hp=h(2mKE)

λ∝1m\lambda \propto \frac{1}{\sqrt{m}} as all the particles have same KE.

Since m_e &lt; m_p &lt; m_{\mathrm{n}} &lt; m_\alpha

λe>λp>λn>λα

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