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QJEEM22Phf5ba: JEE Main 2022 Physics - Class 11 JEEM22Phf5ba Solution: A ball is projected vertically upward with an initial velocity…

A ball is projected vertically upward with an initial velocity of 50 ms−1 at t = 0s. At t = 2s, another ball is projected vertically upward with same velocity. At t = __________ s, second ball will meet the first ball (g = 10 ms−2).

Step-by-Step Verified Solution

At t = 2 s, v1 = 50 − 2 × 10 = 30 m/s

v2 = v2

∴ arel = g − g = 0

S=u2−v22g=502−3022×10=160020=80 m

∴ vrel = 50 − 30 = 20 m/s

∴ Δt=8020=4s

∴ required time t = 2 + 4 = 6 s

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