Verified Solution • 2025–26 Session moderate

QJEEM22Phf46b: JEE Main 2022 Physics - Class 11 JEEM22Phf46b Solution: The dimension of mutual inductance is :

The dimension of mutual inductance is :

Multiple Choice Options

A $[M{L^2}{T^{ - 2}}{A^{ - 1}}]$
B $[M{L^2}{T^{ - 3}}{A^{ - 1}}]$
C $[M{L^2}{T^{ - 2}}{A^{ - 2}}]$
D $[M{L^2}{T^{ - 3}}{A^{ - 2}}]$

Step-by-Step Verified Solution

$\because$ $U = {1 \over 2}M{i^2}$

$\Rightarrow [M] = {{[U]} \over {[{i^2}]}} = {{M{L^2}{T^{ - 2}}} \over {{A^2}}}$

$= [M{L^2}{T^{ - 2}}{A^{ - 2}}]$

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring