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QJEEM22Phef9c: JEE Main 2022 Physics - Class 12 JEEM22Phef9c Solution: An EM wave propagating in x-direction has a wavelength of 8 mm. …
An EM wave propagating in x-direction has a wavelength of 8 mm. The electric field vibrating y-direction has maximum magnitude of 60 Vm
Multiple Choice Options
- A Ey=60sin[π4×103(x−3×108t)]j^Vm−1 Bz=2sin[π4×103(x−3×108t)]k^T
- B Ey=60sin[π4×103(x−3×108t)]j^Vm−1 Bz=2×10−7sin[π4×103(x−3×108t)]k^T
- C Ey=2×10−7sin[π4×103(x−3×108t)]j^Vm−1 Bz=60sin[π4×103(x−3×108t)]k^T
- D Ey=2×10−7sin[π4×104(x−4×108t)]j^Vm−1 Bz=60sin[π4×104(x−4×108t)]k^T
Step-by-Step Verified Solution
In first 3 options speed of light is 3
Using
E = CB
We can check the option is B.