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QJEEM22Pheec3: JEE Main 2022 Physics - Class 12 JEEM22Pheec3 Solution: A wire of length carrying current of is bent to form a circle.…

A wire of length 314 cm314 \mathrm{~cm} carrying current of 14 A14 \mathrm{~A} is bent to form a circle. The magnetic moment of the coil is ________ A −m2-\mathrm{m}^{2} . [Given π=3.14\pi=3.14 ]

Step-by-Step Verified Solution

R=l2π=3142×3.14=50R = {l \over {2\pi }} = {{314} \over {2 \times 3.14}} = 50 cm

μ=πR2i\mu = \pi {R^2}i

=14×3.14×(0.5)2= 14 \times 3.14 \times {(0.5)^2}

=11= 11 A-m2

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