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QJEEM22Phee92: JEE Main 2022 Physics - Class 12 JEEM22Phee92 Solution: A force of 10 N acts on a charged particle placed between two…

A force of 10 N acts on a charged particle placed between two plates of a charged capacitor. If one plate of capacitor is removed, then the force acting on that particle will be.

Multiple Choice Options

  • A 5 N
  • B 10 N
  • C 20 N
  • D Zero

Step-by-Step Verified Solution

E between two plates is σε0{\sigma \over {{\varepsilon _0}}} and due to one plate is σ2ε0{\sigma \over {2{\varepsilon _0}}} so the force will be halved

So new force F = 5 N

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