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QJEEM22Phea96: JEE Main 2022 Physics - Class 11 JEEM22Phea96 Solution: A string of area of cross-section 4   mm 2 and length 0.5…

A string of area of cross-section 4 mm2 and length 0.5 m is connected with a rigid body of mass 2 kg. The body is rotated in a vertical circular path of radius 0.5 m. The body acquires a speed of 5 m/s at the bottom of the circular path. Strain produced in the string when the body is at the bottom of the circle is _________ ×10−5.

(use Young's modulus 1011 N/m2 and g=10 m/s2)

Step-by-Step Verified Solution

A=4×10−6 m2

l=0.5 m

m=2 kg

vb=5 m/s

Tb=mg+m(Vb2l)

=20+2×2512=120 N

Δll=TbA×1Y=1204×10−6×10−11=30×10−5

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