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QJEEM22Phe7ca: JEE Main 2022 Physics - Class 11 JEEM22Phe7ca Solution: The position vector of 1 kg object is r → = ( 3 i ^ − j ^ ) m…

The position vector of 1 kg object is r→=(3i^−j^)m and its velocity v→=(3j^+k^)ms−1. The magnitude of its angular momentum is x Nm where x is ___________.

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|i→|=|r→×(mv→)|

=|(3i^−j^)×(3j^+k^)|

=|−i^−3j^+9k^|

=91

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