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QJEEM22Phdfd6: JEE Main 2022 Physics - Class 11 JEEM22Phdfd6 Solution: A particle is moving in a straight line such that its velocity…

A particle is moving in a straight line such that its velocity is increasing at 5 ms −- 1 per meter. The acceleration of the particle is _____________ ms −- 2 at a point where its velocity is 20 ms −- 1.

Step-by-Step Verified Solution

dvdx=5{{dv} \over {dx}} = 5 ms −- 1/m

Acceleration of particle

when v=20v = 20 m/s

a=vdvdx=20(5)a = v{{dv} \over {dx}} = 20(5) m/s2 = 100 m/s2

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