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QJEEM22Phdfc9: JEE Main 2022 Physics - Class 12 JEEM22Phdfc9 Solution: In Young's double slit experiment, the fringe width is . If the …

In Young's double slit experiment, the fringe width is 12 mm12 \mathrm{~mm} . If the entire arrangement is placed in water of refractive index 43\frac{4}{3} , then the fringe width becomes (in mm):

Multiple Choice Options

  • A 16
  • B 9
  • C 48
  • D 12

Step-by-Step Verified Solution

B=12×10−3B = 12 \times {10^{ - 3}}

β′=βμ=12×10−343\beta ' = {\beta \over \mu } = {{12 \times {{10}^{ - 3}}} \over {{4 \over 3}}}

=9×10−3= 9 \times {10^{ - 3}} m = 9 mm

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