Verified Solution • 2025–26 Session moderate

QJEEM22Phdcb1: JEE Main 2022 Physics - Class 11 JEEM22Phdcb1 Solution: A particle experiences a variable force F → = ( 4 x i ^ + 3 y 2 …

A particle experiences a variable force F→=(4xi^+3y2j^) in a horizontal x-y plane. Assume distance in meters and force is newton. If the particle moves from point (1, 2) to point (2, 3) in the x-y plane, then Kinetic Energy changes by :

Multiple Choice Options

  • A 50.0 J
  • B 12.5 J
  • C 25.0 J
  • D 0 J

Step-by-Step Verified Solution

W=∫F→.dr→

=∫124xdx+∫233y2dy

=[2x2]12+[y3]23

=2×3+(27−8)

=25 J

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