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QJEEM22Phd8fc: JEE Main 2022 Physics - Class 12 JEEM22Phd8fc Solution: A 10 , 20 mH coil carrying constant current is connected to a…

A 10 Ω\Omega , 20 mH coil carrying constant current is connected to a battery of 20 V through a switch. Now after switch is opened current becomes zero in 100 μ\mu s. The average e.m.f. induced in the coil is ____________ V.

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JEE Main 2022 (Online) 26th June Morning Shift Physics - Electromagnetic Induction Question 58 English Explanation

Initially current, I0=2010=2A{I_0} = {{20} \over {10}} = 2A (when initially switch closed)

average emf induced in coil =Ldidt= {{Ldi} \over {dt}}

⇒eavg=20×10−3×(2−0)100×10−6\Rightarrow {e_{avg}} = {{20 \times {{10}^{ - 3}} \times (2 - 0)} \over {100 \times {{10}^{ - 6}}}}

eavg=400 V{e_{avg}} = 400\,V

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