Verified Solution • 2025–26 Session moderate

QJEEM22Phd477: JEE Main 2022 Physics - Class 12 JEEM22Phd477 Solution: A direct current of and an alternating current of peak value…

A direct current of 4 A4 \mathrm{~A} and an alternating current of peak value 4 A4 \mathrm{~A} flow through resistance of 3 Ω3\, \Omega and 2 Ω2\,\Omega respectively. The ratio of heat produced in the two resistances in same interval of time will be :

Multiple Choice Options

  • A 3:02
  • B 3:01
  • C 3:04
  • D 4:03

Step-by-Step Verified Solution

Ratio = i12R1(i22)2R2=42×3(42)2×2{{i_1^2{R_1}} \over {{{\left( {{{{i_2}} \over {\sqrt 2 }}} \right)}^2}{R_2}}} = {{{4^2} \times 3} \over {{{\left( {{4 \over {\sqrt 2 }}} \right)}^2} \times 2}}

⇒\Rightarrow Ratio = 3 : 1

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