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QJEEM22Phce08: JEE Main 2022 Physics - Class 11 JEEM22Phce08 Solution: The total internal energy of two mole monoatomic ideal gas at…

The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be _____________ J. (Given R = 8.31 J/mol.K)

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U=2(32R)300U = 2\left( {{3 \over 2}R} \right)300

=3×8.31×300= 3 \times 8.31 \times 300

=7479= 7479 J

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