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QJEEM22Phccc1: JEE Main 2022 Physics - Class 12 JEEM22Phccc1 Solution: The required height of a TV tower which can cover the…

The required height of a TV tower which can cover the population of 6.036.03 lakh is hh . If the average population density is 100 per square km\mathrm{km} and the radius of earth is 6400 km6400 \mathrm{~km} , then the value of hh will be _____________ mm .

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JEE Main 2022 (Online) 25th July Morning Shift Physics - Communication Systems Question 34 English Explanation

r=(h+R)2−R2≅2hRr = \sqrt {{{(h + R)}^2} - {R^2}} \cong \sqrt {2hR}

A=6.03×105100A = {{6.03 \times {{10}^5}} \over {100}}

πr2=6.03×103\pi {r^2} = 6.03 \times {10^3}

π2Rh=6.03×103\pi 2Rh = 6.03 \times {10^3}

h=6.03×1032×π×R=0.015×10×103h = {{6.03 \times {{10}^3}} \over {2 \times \pi \times R}} = 0.015 \times 10 \times {10^3} m

=150=150 m

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